T=16t^2+8t+1

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Solution for T=16t^2+8t+1 equation: 



=16T^2+8T+1

We move all terms to the left:

-(16T^2+8T+1)=0

We get rid of parentheses

-16T^2-8T-1=0

a = -16; b = -8; c = -1;
Δ = b2-4ac
Δ = -82-4·(-16)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$T=\frac{-b}{2a}=\frac{8}{-32}=-1/4$

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